141131401212434 has 4 divisors (see below), whose sum is σ = 211697101818654. Its totient is φ = 70565700606216.

The previous prime is 141131401212433. The next prime is 141131401212437. The reversal of 141131401212434 is 434212104131141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 131299445208409 + 9831956004025 = 11458597^2 + 3135595^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 141131401212434.

It is not an unprimeable number, because it can be changed into a prime (141131401212433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35282850303107 + ... + 35282850303110.

Almost surely, 2^{141131401212434} is an apocalyptic number.

141131401212434 is a deficient number, since it is larger than the sum of its proper divisors (70565700606220).

141131401212434 is an equidigital number, since it uses as much as digits as its factorization.

141131401212434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70565700606219.

The product of its (nonzero) digits is 9216, while the sum is 32.

Adding to 141131401212434 its reverse (434212104131141), we get a palindrome (575343505343575).

The spelling of 141131401212434 in words is "one hundred forty-one trillion, one hundred thirty-one billion, four hundred one million, two hundred twelve thousand, four hundred thirty-four".