Base | Representation |
---|---|
bin | 100000000101101110110111… |
… | …100101011001011110000001 |
3 | 200111201000211122112122012220 |
4 | 200011232313211121132001 |
5 | 121444244112031212231 |
6 | 1220054512550441253 |
7 | 41504256626106030 |
oct | 4005566745313601 |
9 | 614630748478186 |
10 | 141131410413441 |
11 | 40a72549987808 |
12 | 139b4267963229 |
13 | 6099833b37316 |
14 | 26bcb22262717 |
15 | 114b242816896 |
hex | 805bb7959781 |
141131410413441 has 16 divisors (see below), whose sum is σ = 217274473766784. Its totient is φ = 79815112809984.
The previous prime is 141131410413401. The next prime is 141131410413473. The reversal of 141131410413441 is 144314014131141.
It is not a de Polignac number, because 141131410413441 - 234 = 141114230544257 is a prime.
It is not an unprimeable number, because it can be changed into a prime (141131410413401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34641974010 + ... + 34641978083.
It is an arithmetic number, because the mean of its divisors is an integer number (13579654610424).
Almost surely, 2141131410413441 is an apocalyptic number.
It is an amenable number.
141131410413441 is a deficient number, since it is larger than the sum of its proper divisors (76143063353343).
141131410413441 is an equidigital number, since it uses as much as digits as its factorization.
141131410413441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69283952200.
The product of its (nonzero) digits is 9216, while the sum is 33.
Adding to 141131410413441 its reverse (144314014131141), we get a palindrome (285445424544582).
The spelling of 141131410413441 in words is "one hundred forty-one trillion, one hundred thirty-one billion, four hundred ten million, four hundred thirteen thousand, four hundred forty-one".
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