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14113221051 = 311714017427
BaseRepresentation
bin11010010010011011…
…01010100110111011
31100102120111220122210
431021031222212323
5212400441033201
610252235150203
71006511254026
oct151115524673
940376456583
1014113221051
115a925aa956
12289a5a5363
13143bc01397
1497c54a1bd
1557904a1d6
hex34936a9bb

14113221051 has 8 divisors (see below), whose sum is σ = 18833702464. Its totient is φ = 9400776840.

The previous prime is 14113221029. The next prime is 14113221079. The reversal of 14113221051 is 15012231141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14113221051 - 226 = 14046112187 is a prime.

It is a super-3 number, since 3×141132210513 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14113223051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2005201 + ... + 2012226.

It is an arithmetic number, because the mean of its divisors is an integer number (2354212808).

Almost surely, 214113221051 is an apocalyptic number.

14113221051 is a deficient number, since it is larger than the sum of its proper divisors (4720481413).

14113221051 is a wasteful number, since it uses less digits than its factorization.

14113221051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4018601.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 14113221051 its reverse (15012231141), we get a palindrome (29125452192).

The spelling of 14113221051 in words is "fourteen billion, one hundred thirteen million, two hundred twenty-one thousand, fifty-one".

Divisors: 1 3 1171 3513 4017427 12052281 4704407017 14113221051