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141132341343242 = 22322313758270749
BaseRepresentation
bin100000000101101111101111…
…000100100111010000001010
3200111201010020112020202211102
4200011233233010213100022
5121444303013340440432
61220055145203501402
741504321661635054
oct4005575704472012
9614633215222742
10141132341343242
1140a72987415087
12139b4487687862
13609995196cc62
1426bcbadb508d4
15114b299402962
hex805bef12740a

141132341343242 has 16 divisors (see below), whose sum is σ = 221893390656000. Its totient is φ = 67195394333232.

The previous prime is 141132341343221. The next prime is 141132341343307. The reversal of 141132341343242 is 242343143231141.

It is a super-3 number, since 3×1411323413432423 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141132341343196 and 141132341343205.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6879125117 + ... + 6879145632.

It is an arithmetic number, because the mean of its divisors is an integer number (13868336916000).

Almost surely, 2141132341343242 is an apocalyptic number.

141132341343242 is a deficient number, since it is larger than the sum of its proper divisors (80761049312758).

141132341343242 is a wasteful number, since it uses less digits than its factorization.

141132341343242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13758270997.

The product of its digits is 165888, while the sum is 38.

Adding to 141132341343242 its reverse (242343143231141), we get a palindrome (383475484574383).

The spelling of 141132341343242 in words is "one hundred forty-one trillion, one hundred thirty-two billion, three hundred forty-one million, three hundred forty-three thousand, two hundred forty-two".

Divisors: 1 2 23 46 223 446 5129 10258 13758270749 27516541498 316440227227 632880454454 3068094377027 6136188754054 70566170671621 141132341343242