141132410042400 has 432 divisors, whose sum is σ = 569125970981568. Its totient is φ = 32238284544000.

The previous prime is 141132410042389. The next prime is 141132410042431. The reversal of 141132410042400 is 4240014231141.

141132410042400 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 3 + 2 + 410 + 0 + 4 + 240 + 0 = 666.

It is a super-3 number, since 3×141132410042400³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 78287170 + ... + 80069630.

It is an arithmetic number, because the mean of its divisors is an integer number (1317421229124).

Almost surely, 2^{141132410042400} is an apocalyptic number.

141132410042400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 141132410042400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (284562985490784).

141132410042400 is an abundant number, since it is smaller than the sum of its proper divisors (427993560939168).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141132410042400 is a wasteful number, since it uses less digits than its factorization.

141132410042400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1784065 (or 1784049 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 27.

Adding to 141132410042400 its reverse (4240014231141), we get a palindrome (145372424273541).

The spelling of 141132410042400 in words is "one hundred forty-one trillion, one hundred thirty-two billion, four hundred ten million, forty-two thousand, four hundred".