141134402011041 has 32 divisors (see below), whose sum is σ = 211162874797440. Its totient is φ = 93155950440000.

The previous prime is 141134402011039. The next prime is 141134402011093. The reversal of 141134402011041 is 140110204431141.

141134402011041 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 3 + 440 + 201 + 10 + 4 + 1 = 666.

141134402011041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 141134402011041 - 2¹ = 141134402011039 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 141134402010996 and 141134402011014.

It is not an unprimeable number, because it can be changed into a prime (141134402011441) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 127347286 + ... + 128450768.

It is an arithmetic number, because the mean of its divisors is an integer number (6598839837420).

Almost surely, 2^{141134402011041} is an apocalyptic number.

It is an amenable number.

141134402011041 is a deficient number, since it is larger than the sum of its proper divisors (70028472786399).

141134402011041 is a wasteful number, since it uses less digits than its factorization.

141134402011041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1150494 (or 1150488 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 27.

Adding to 141134402011041 its reverse (140110204431141), we get a palindrome (281244606442182).

The spelling of 141134402011041 in words is "one hundred forty-one trillion, one hundred thirty-four billion, four hundred two million, eleven thousand, forty-one".