Base | Representation |
---|---|
bin | 100000000101110001101100… |
… | …001010011110101101100011 |
3 | 200111201022122210022021010021 |
4 | 200011301230022132231203 |
5 | 121444321313122024443 |
6 | 1220100133334014311 |
7 | 41504424664334335 |
oct | 4005615412365543 |
9 | 614638583267107 |
10 | 141134440033123 |
11 | 40a73864038929 |
12 | 139b49724a7397 |
13 | 6099bc76bc6a4 |
14 | 26bcd2c779455 |
15 | 114b36d7ab9ed |
hex | 805c6c29eb63 |
141134440033123 has 2 divisors, whose sum is σ = 141134440033124. Its totient is φ = 141134440033122.
The previous prime is 141134440033073. The next prime is 141134440033127. The reversal of 141134440033123 is 321330044431141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141134440033123 - 217 = 141134439902051 is a prime.
It is a super-2 number, since 2×1411344400331232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (141134440033127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70567220016561 + 70567220016562.
It is an arithmetic number, because the mean of its divisors is an integer number (70567220016562).
Almost surely, 2141134440033123 is an apocalyptic number.
141134440033123 is a deficient number, since it is larger than the sum of its proper divisors (1).
141134440033123 is an equidigital number, since it uses as much as digits as its factorization.
141134440033123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 141134440033123 its reverse (321330044431141), we get a palindrome (462464484464264).
The spelling of 141134440033123 in words is "one hundred forty-one trillion, one hundred thirty-four billion, four hundred forty million, thirty-three thousand, one hundred twenty-three".
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