Base | Representation |
---|---|
bin | 1000001101110001000… |
… | …1001011010111100011 |
3 | 111111021220100121100202 |
4 | 2003130101023113203 |
5 | 4303020404202003 |
6 | 144500344535415 |
7 | 13124304660140 |
oct | 2033421132743 |
9 | 444256317322 |
10 | 141134444003 |
11 | 54944794773 |
12 | 2342978156b |
13 | 10402912637 |
14 | 6b8c1753c7 |
15 | 3a1060d088 |
hex | 20dc44b5e3 |
141134444003 has 4 divisors (see below), whose sum is σ = 161296507440. Its totient is φ = 120972380568.
The previous prime is 141134443997. The next prime is 141134444029. The reversal of 141134444003 is 300444431141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 300444431141 = 2053 ⋅146344097.
It is a cyclic number.
It is not a de Polignac number, because 141134444003 - 214 = 141134427619 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141134444083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10081031708 + ... + 10081031721.
It is an arithmetic number, because the mean of its divisors is an integer number (40324126860).
Almost surely, 2141134444003 is an apocalyptic number.
141134444003 is a deficient number, since it is larger than the sum of its proper divisors (20162063437).
141134444003 is an equidigital number, since it uses as much as digits as its factorization.
141134444003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20162063436.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 141134444003 its reverse (300444431141), we get a palindrome (441578875144).
The spelling of 141134444003 in words is "one hundred forty-one billion, one hundred thirty-four million, four hundred forty-four thousand, three".
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