14114104445033 has 4 divisors (see below), whose sum is σ = 14324762720400. Its totient is φ = 13903446169668.

The previous prime is 14114104445017. The next prime is 14114104445107. The reversal of 14114104445033 is 33054440141141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14114104445033 - 2⁴ = 14114104445017 is a prime.

It is a super-4 number, since 4×14114104445033⁴ (a number of 54 digits) contains 4444 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14114104444984 and 14114104445002.

It is not an unprimeable number, because it can be changed into a prime (14114104445003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105329137583 + ... + 105329137716.

It is an arithmetic number, because the mean of its divisors is an integer number (3581190680100).

Almost surely, 2^{14114104445033} is an apocalyptic number.

It is an amenable number.

14114104445033 is a deficient number, since it is larger than the sum of its proper divisors (210658275367).

14114104445033 is an equidigital number, since it uses as much as digits as its factorization.

14114104445033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 210658275366.

The product of its (nonzero) digits is 46080, while the sum is 35.

Adding to 14114104445033 its reverse (33054440141141), we get a palindrome (47168544586174).

The spelling of 14114104445033 in words is "fourteen trillion, one hundred fourteen billion, one hundred four million, four hundred forty-five thousand, thirty-three".