Base | Representation |
---|---|
bin | 100000000101110111111111… |
… | …001001101011011011011001 |
3 | 200111201222002222100001111121 |
4 | 200011313333021223123121 |
5 | 121444424134431303423 |
6 | 1220103212253525241 |
7 | 41505054352060030 |
oct | 4005677711533331 |
9 | 614658088301447 |
10 | 141141201041113 |
11 | 40a76713498239 |
12 | 139b613a7a3821 |
13 | 609a734338530 |
14 | 26bd3b0683717 |
15 | 114b61711845d |
hex | 805dff26b6d9 |
141141201041113 has 32 divisors (see below), whose sum is σ = 173892139545600. Its totient is φ = 111556531791360.
The previous prime is 141141201041063. The next prime is 141141201041119. The reversal of 141141201041113 is 311140102141141.
It is a cyclic number.
It is not a de Polignac number, because 141141201041113 - 217 = 141141200910041 is a prime.
It is not an unprimeable number, because it can be changed into a prime (141141201041119) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1308784431 + ... + 1308892267.
It is an arithmetic number, because the mean of its divisors is an integer number (5434129360800).
Almost surely, 2141141201041113 is an apocalyptic number.
141141201041113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
141141201041113 is a deficient number, since it is larger than the sum of its proper divisors (32750938504487).
141141201041113 is a wasteful number, since it uses less digits than its factorization.
141141201041113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 122617.
The product of its (nonzero) digits is 384, while the sum is 25.
Adding to 141141201041113 its reverse (311140102141141), we get a palindrome (452281303182254).
The spelling of 141141201041113 in words is "one hundred forty-one trillion, one hundred forty-one billion, two hundred one million, forty-one thousand, one hundred thirteen".
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