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1411422441113 is a prime number
BaseRepresentation
bin10100100010011111010…
…101010100111010011001
311222221010110022220222102
4110202133111110322121
5141111043121103423
63000222025133145
7203654235541436
oct24423725247231
94887113286872
101411422441113
114a4643199373
121a966262a1b5
13a31341cc379
144c455642b8d
1526aaad46c28
hex1489f554e99

1411422441113 has 2 divisors, whose sum is σ = 1411422441114. Its totient is φ = 1411422441112.

The previous prime is 1411422441031. The next prime is 1411422441157. The reversal of 1411422441113 is 3111442241141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1333015720969 + 78406720144 = 1154563^2 + 280012^2 .

It is a cyclic number.

It is not a de Polignac number, because 1411422441113 - 222 = 1411418246809 is a prime.

It is a super-2 number, since 2×14114224411132 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1411422441173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705711220556 + 705711220557.

It is an arithmetic number, because the mean of its divisors is an integer number (705711220557).

Almost surely, 21411422441113 is an apocalyptic number.

It is an amenable number.

1411422441113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411422441113 is an equidigital number, since it uses as much as digits as its factorization.

1411422441113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3072, while the sum is 29.

Adding to 1411422441113 its reverse (3111442241141), we get a palindrome (4522864682254).

The spelling of 1411422441113 in words is "one trillion, four hundred eleven billion, four hundred twenty-two million, four hundred forty-one thousand, one hundred thirteen".