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1411443540121 is a prime number
BaseRepresentation
bin10100100010100000100…
…101110100000010011001
311222221011221000212101011
4110202200211310002121
5141111114021240441
63000224101253521
7203654613065536
oct24424045640231
94887157025334
101411443540121
114a465409a36a
121a96697042a1
13a31386a8aa4
144c458375d8d
1526aacb13581
hex148a0974099

1411443540121 has 2 divisors, whose sum is σ = 1411443540122. Its totient is φ = 1411443540120.

The previous prime is 1411443540083. The next prime is 1411443540181. The reversal of 1411443540121 is 1210453441141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1315297034496 + 96146505625 = 1146864^2 + 310075^2 .

It is a cyclic number.

It is not a de Polignac number, because 1411443540121 - 229 = 1410906669209 is a prime.

It is not a weakly prime, because it can be changed into another prime (1411443540181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705721770060 + 705721770061.

It is an arithmetic number, because the mean of its divisors is an integer number (705721770061).

Almost surely, 21411443540121 is an apocalyptic number.

It is an amenable number.

1411443540121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411443540121 is an equidigital number, since it uses as much as digits as its factorization.

1411443540121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 1411443540121 its reverse (1210453441141), we get a palindrome (2621896981262).

The spelling of 1411443540121 in words is "one trillion, four hundred eleven billion, four hundred forty-three million, five hundred forty thousand, one hundred twenty-one".