Base | Representation |
---|---|
bin | 10100100010100000100… |
… | …101110100000010011001 |
3 | 11222221011221000212101011 |
4 | 110202200211310002121 |
5 | 141111114021240441 |
6 | 3000224101253521 |
7 | 203654613065536 |
oct | 24424045640231 |
9 | 4887157025334 |
10 | 1411443540121 |
11 | 4a465409a36a |
12 | 1a96697042a1 |
13 | a31386a8aa4 |
14 | 4c458375d8d |
15 | 26aacb13581 |
hex | 148a0974099 |
1411443540121 has 2 divisors, whose sum is σ = 1411443540122. Its totient is φ = 1411443540120.
The previous prime is 1411443540083. The next prime is 1411443540181. The reversal of 1411443540121 is 1210453441141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1315297034496 + 96146505625 = 1146864^2 + 310075^2 .
It is a cyclic number.
It is not a de Polignac number, because 1411443540121 - 229 = 1410906669209 is a prime.
It is not a weakly prime, because it can be changed into another prime (1411443540181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705721770060 + 705721770061.
It is an arithmetic number, because the mean of its divisors is an integer number (705721770061).
Almost surely, 21411443540121 is an apocalyptic number.
It is an amenable number.
1411443540121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411443540121 is an equidigital number, since it uses as much as digits as its factorization.
1411443540121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 1411443540121 its reverse (1210453441141), we get a palindrome (2621896981262).
The spelling of 1411443540121 in words is "one trillion, four hundred eleven billion, four hundred forty-three million, five hundred forty thousand, one hundred twenty-one".
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