14115143340241 has 4 divisors (see below), whose sum is σ = 14115364648000. Its totient is φ = 14114922032484.

The previous prime is 14115143340173. The next prime is 14115143340251. The reversal of 14115143340241 is 14204334151141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14115143340241 - 2³³ = 14106553405649 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14115143340197 and 14115143340206.

It is not an unprimeable number, because it can be changed into a prime (14115143340251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110558181 + ... + 110685778.

It is an arithmetic number, because the mean of its divisors is an integer number (3528841162000).

Almost surely, 2^{14115143340241} is an apocalyptic number.

It is an amenable number.

14115143340241 is a deficient number, since it is larger than the sum of its proper divisors (221307759).

14115143340241 is an equidigital number, since it uses as much as digits as its factorization.

14115143340241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 221307758.

The product of its (nonzero) digits is 23040, while the sum is 34.

Adding to 14115143340241 its reverse (14204334151141), we get a palindrome (28319477491382).

The spelling of 14115143340241 in words is "fourteen trillion, one hundred fifteen billion, one hundred forty-three million, three hundred forty thousand, two hundred forty-one".