141152504321131 has 4 divisors (see below), whose sum is σ = 141181060365792. Its totient is φ = 141123948276472.

The previous prime is 141152504321107. The next prime is 141152504321243. The reversal of 141152504321131 is 131123405251141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141152504321131 - 2³³ = 141143914386539 is a prime.

It is a super-3 number, since 3×141152504321131³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141152504321431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14278014916 + ... + 14278024801.

It is an arithmetic number, because the mean of its divisors is an integer number (35295265091448).

Almost surely, 2^{141152504321131} is an apocalyptic number.

141152504321131 is a deficient number, since it is larger than the sum of its proper divisors (28556044661).

141152504321131 is an equidigital number, since it uses as much as digits as its factorization.

141152504321131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28556044660.

The product of its (nonzero) digits is 14400, while the sum is 34.

Adding to 141152504321131 its reverse (131123405251141), we get a palindrome (272275909572272).

The spelling of 141152504321131 in words is "one hundred forty-one trillion, one hundred fifty-two billion, five hundred four million, three hundred twenty-one thousand, one hundred thirty-one".