141153123404011 has 2 divisors, whose sum is σ = 141153123404012. Its totient is φ = 141153123404010.

The previous prime is 141153123403961. The next prime is 141153123404021. The reversal of 141153123404011 is 110404321351141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141153123404011 - 2¹⁹ = 141153122879723 is a prime.

It is not a weakly prime, because it can be changed into another prime (141153123404021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70576561702005 + 70576561702006.

It is an arithmetic number, because the mean of its divisors is an integer number (70576561702006).

Almost surely, 2^{141153123404011} is an apocalyptic number.

141153123404011 is a deficient number, since it is larger than the sum of its proper divisors (1).

141153123404011 is an equidigital number, since it uses as much as digits as its factorization.

141153123404011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 141153123404011 its reverse (110404321351141), we get a palindrome (251557444755152).

The spelling of 141153123404011 in words is "one hundred forty-one trillion, one hundred fifty-three billion, one hundred twenty-three million, four hundred four thousand, eleven".