141167380243 has 4 divisors (see below), whose sum is σ = 141168444120. Its totient is φ = 141166316368.

The previous prime is 141167380187. The next prime is 141167380247. The reversal of 141167380243 is 342083761141.

141167380243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 141167380243 - 2¹³ = 141167372051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141167380196 and 141167380205.

It is not an unprimeable number, because it can be changed into a prime (141167380247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298858 + ... + 609631.

It is an arithmetic number, because the mean of its divisors is an integer number (35292111030).

Almost surely, 2^141167380243 is an apocalyptic number.

141167380243 is a deficient number, since it is larger than the sum of its proper divisors (1063877).

141167380243 is an equidigital number, since it uses as much as digits as its factorization.

141167380243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1063876.

The product of its (nonzero) digits is 96768, while the sum is 40.

The spelling of 141167380243 in words is "one hundred forty-one billion, one hundred sixty-seven million, three hundred eighty thousand, two hundred forty-three".