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1412002431331 = 4123907214993
BaseRepresentation
bin10100100011000001111…
…001110100000101100011
311222222121212200110222121
4110203001321310011203
5141113240110300311
63000355344245111
7204004510431142
oct24430171640543
94888555613877
101412002431331
114a491061a628
121a97a4910797
13a31c741024b
144c4ac69b759
1526ae1c10b71
hex148c1e74163

1412002431331 has 12 divisors (see below), whose sum is σ = 1447658659096. Its totient is φ = 1377204353280.

The previous prime is 1412002431317. The next prime is 1412002431407. The reversal of 1412002431331 is 1331342002141.

It is not a de Polignac number, because 1412002431331 - 211 = 1412002429283 is a prime.

It is a super-2 number, since 2×14120024313312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1412002431296 and 1412002431305.

It is not an unprimeable number, because it can be changed into a prime (1412002431031) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6460171 + ... + 6675163.

Almost surely, 21412002431331 is an apocalyptic number.

1412002431331 is a deficient number, since it is larger than the sum of its proper divisors (35656227765).

1412002431331 is an equidigital number, since it uses as much as digits as its factorization.

1412002431331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 218982 (or 218941 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1412002431331 its reverse (1331342002141), we get a palindrome (2743344433472).

The spelling of 1412002431331 in words is "one trillion, four hundred twelve billion, two million, four hundred thirty-one thousand, three hundred thirty-one".

Divisors: 1 41 1681 3907 160187 214993 6567667 8814713 361403233 839977651 34439083691 1412002431331