Base | Representation |
---|---|
bin | 10100100011000001111… |
… | …001110100000101100011 |
3 | 11222222121212200110222121 |
4 | 110203001321310011203 |
5 | 141113240110300311 |
6 | 3000355344245111 |
7 | 204004510431142 |
oct | 24430171640543 |
9 | 4888555613877 |
10 | 1412002431331 |
11 | 4a491061a628 |
12 | 1a97a4910797 |
13 | a31c741024b |
14 | 4c4ac69b759 |
15 | 26ae1c10b71 |
hex | 148c1e74163 |
1412002431331 has 12 divisors (see below), whose sum is σ = 1447658659096. Its totient is φ = 1377204353280.
The previous prime is 1412002431317. The next prime is 1412002431407. The reversal of 1412002431331 is 1331342002141.
It is not a de Polignac number, because 1412002431331 - 211 = 1412002429283 is a prime.
It is a super-2 number, since 2×14120024313312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1412002431296 and 1412002431305.
It is not an unprimeable number, because it can be changed into a prime (1412002431031) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6460171 + ... + 6675163.
Almost surely, 21412002431331 is an apocalyptic number.
1412002431331 is a deficient number, since it is larger than the sum of its proper divisors (35656227765).
1412002431331 is an equidigital number, since it uses as much as digits as its factorization.
1412002431331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 218982 (or 218941 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1412002431331 its reverse (1331342002141), we get a palindrome (2743344433472).
The spelling of 1412002431331 in words is "one trillion, four hundred twelve billion, two million, four hundred thirty-one thousand, three hundred thirty-one".
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