141201243330113 has 8 divisors (see below), whose sum is σ = 142657270049448. Its totient is φ = 139745223627264.

The previous prime is 141201243330101. The next prime is 141201243330151. The reversal of 141201243330113 is 311033342102141.

141201243330113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 25424869966864 + 115776373363249 = 5042308^2 + 10759943^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141201243330113 - 2²⁸ = 141200974894657 is a prime.

It is a super-2 number, since 2×141201243330113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141201243330163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45129095 + ... + 48156387.

It is an arithmetic number, because the mean of its divisors is an integer number (17832158756181).

Almost surely, 2^{141201243330113} is an apocalyptic number.

It is an amenable number.

141201243330113 is a deficient number, since it is larger than the sum of its proper divisors (1456026719335).

141201243330113 is an equidigital number, since it uses as much as digits as its factorization.

141201243330113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3508243.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 141201243330113 its reverse (311033342102141), we get a palindrome (452234585432254).

The spelling of 141201243330113 in words is "one hundred forty-one trillion, two hundred one billion, two hundred forty-three million, three hundred thirty thousand, one hundred thirteen".