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141201353 is a prime number
BaseRepresentation
bin10000110101010…
…00111111001001
3100211200202211202
420122220333021
5242121420403
622002233545
73333122516
oct1032507711
9324622752
10141201353
1172782737
123b3558b5
132333b0c7
1414a7830d
15c5e2688
hex86a8fc9

141201353 has 2 divisors, whose sum is σ = 141201354. Its totient is φ = 141201352.

The previous prime is 141201349. The next prime is 141201383. The reversal of 141201353 is 353102141.

141201353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99042304 + 42159049 = 9952^2 + 6493^2 .

It is a cyclic number.

It is not a de Polignac number, because 141201353 - 22 = 141201349 is a prime.

It is not a weakly prime, because it can be changed into another prime (141201383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70600676 + 70600677.

It is an arithmetic number, because the mean of its divisors is an integer number (70600677).

Almost surely, 2141201353 is an apocalyptic number.

It is an amenable number.

141201353 is a deficient number, since it is larger than the sum of its proper divisors (1).

141201353 is an equidigital number, since it uses as much as digits as its factorization.

141201353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360, while the sum is 20.

The square root of 141201353 is about 11882.8175530890. The cubic root of 141201353 is about 520.7304244567.

Adding to 141201353 its reverse (353102141), we get a palindrome (494303494).

The spelling of 141201353 in words is "one hundred forty-one million, two hundred one thousand, three hundred fifty-three".