Search a number
-
+
141202040020114 = 270601020010057
BaseRepresentation
bin100000000110110000101001…
…011011111101110010010010
3200111221210010221121102002011
4200012300221123331302102
5122001423234221120424
61220151153252213134
741512340116624453
oct4006605133756222
9614853127542064
10141202040020114
1140a9a4a3509677
1213a05a9960a1aa
1360a33ab8454a8
1426c230272b12a
15114cec8342694
hex806c296fdc92

141202040020114 has 4 divisors (see below), whose sum is σ = 211803060030174. Its totient is φ = 70601020010056.

The previous prime is 141202040020109. The next prime is 141202040020201. The reversal of 141202040020114 is 411020040202141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 109071224776089 + 32130815244025 = 10443717^2 + 5668405^2 .

It is a super-2 number, since 2×1412020400201142 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35300510005027 + ... + 35300510005030.

Almost surely, 2141202040020114 is an apocalyptic number.

141202040020114 is a deficient number, since it is larger than the sum of its proper divisors (70601020010060).

141202040020114 is an equidigital number, since it uses as much as digits as its factorization.

141202040020114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70601020010059.

The product of its (nonzero) digits is 512, while the sum is 22.

Adding to 141202040020114 its reverse (411020040202141), we get a palindrome (552222080222255).

The spelling of 141202040020114 in words is "one hundred forty-one trillion, two hundred two billion, forty million, twenty thousand, one hundred fourteen".

Divisors: 1 2 70601020010057 141202040020114