Base | Representation |
---|---|
bin | 1100110101111001111010… |
… | …1101100010100010001011 |
3 | 1211222212202102111220202102 |
4 | 3031132132231202202023 |
5 | 3322321202340140021 |
6 | 50010423432024015 |
7 | 2655103135466114 |
oct | 315363655424213 |
9 | 54885672456672 |
10 | 14120220240011 |
11 | 4554396237346 |
12 | 170071523200b |
13 | 7b56b9961042 |
14 | 36b5cab4520b |
15 | 1974753aa00b |
hex | cd79eb6288b |
14120220240011 has 2 divisors, whose sum is σ = 14120220240012. Its totient is φ = 14120220240010.
The previous prime is 14120220239989. The next prime is 14120220240037. The reversal of 14120220240011 is 11004202202141.
It is a weak prime.
It is an emirp because it is prime and its reverse (11004202202141) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14120220240011 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (14120220249011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060110120005 + 7060110120006.
It is an arithmetic number, because the mean of its divisors is an integer number (7060110120006).
Almost surely, 214120220240011 is an apocalyptic number.
14120220240011 is a deficient number, since it is larger than the sum of its proper divisors (1).
14120220240011 is an equidigital number, since it uses as much as digits as its factorization.
14120220240011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 256, while the sum is 20.
Adding to 14120220240011 its reverse (11004202202141), we get a palindrome (25124422442152).
The spelling of 14120220240011 in words is "fourteen trillion, one hundred twenty billion, two hundred twenty million, two hundred forty thousand, eleven".
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