Base | Representation |
---|---|
bin | 10100100011000011001… |
… | …001000101011111101011 |
3 | 11222222200022210020201102 |
4 | 110203003021011133223 |
5 | 141113310420241021 |
6 | 3000401405512015 |
7 | 204005152161206 |
oct | 24430311053753 |
9 | 4888608706642 |
10 | 1412023212011 |
11 | 4a4921323445 |
12 | 1a97ab87260b |
13 | a31cb807ac9 |
14 | 4c4b134a93d |
15 | 26ae396800b |
hex | 148c32457eb |
1412023212011 has 2 divisors, whose sum is σ = 1412023212012. Its totient is φ = 1412023212010.
The previous prime is 1412023211917. The next prime is 1412023212029. The reversal of 1412023212011 is 1102123202141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1412023212011 is a prime.
It is a super-2 number, since 2×14120232120112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1412023212091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706011606005 + 706011606006.
It is an arithmetic number, because the mean of its divisors is an integer number (706011606006).
Almost surely, 21412023212011 is an apocalyptic number.
1412023212011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412023212011 is an equidigital number, since it uses as much as digits as its factorization.
1412023212011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1412023212011 its reverse (1102123202141), we get a palindrome (2514146414152).
The spelling of 1412023212011 in words is "one trillion, four hundred twelve billion, twenty-three million, two hundred twelve thousand, eleven".
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