Base | Representation |
---|---|
bin | 100000000110110001101100… |
… | …110100100100000010100011 |
3 | 200111221220001201212212012011 |
4 | 200012301230310210002203 |
5 | 122001433043124313411 |
6 | 1220151501355213351 |
7 | 41512410125121034 |
oct | 4006615464440243 |
9 | 614856051785164 |
10 | 141203170541731 |
11 | 40a9aa23680261 |
12 | 13a06154147257 |
13 | 60a352bb216ac |
14 | 26c23ac932a8b |
15 | 114d042706c21 |
hex | 806c6cd240a3 |
141203170541731 has 2 divisors, whose sum is σ = 141203170541732. Its totient is φ = 141203170541730.
The previous prime is 141203170541711. The next prime is 141203170541759. The reversal of 141203170541731 is 137145071302141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141203170541731 - 215 = 141203170508963 is a prime.
It is a super-2 number, since 2×1412031705417312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (141203170541711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70601585270865 + 70601585270866.
It is an arithmetic number, because the mean of its divisors is an integer number (70601585270866).
Almost surely, 2141203170541731 is an apocalyptic number.
141203170541731 is a deficient number, since it is larger than the sum of its proper divisors (1).
141203170541731 is an equidigital number, since it uses as much as digits as its factorization.
141203170541731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 70560, while the sum is 40.
The spelling of 141203170541731 in words is "one hundred forty-one trillion, two hundred three billion, one hundred seventy million, five hundred forty-one thousand, seven hundred thirty-one".
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