141204032223041 has 4 divisors (see below), whose sum is σ = 141226385250132. Its totient is φ = 141181679195952.

The previous prime is 141204032223019. The next prime is 141204032223097. The reversal of 141204032223041 is 140322230402141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 30004813852225 + 111199218370816 = 5477665^2 + 10545104^2 .

It is a cyclic number.

It is not a de Polignac number, because 141204032223041 - 2¹⁰ = 141204032222017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 141204032222995 and 141204032223013.

It is not an unprimeable number, because it can be changed into a prime (141204032223841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11176504070 + ... + 11176516703.

It is an arithmetic number, because the mean of its divisors is an integer number (35306596312533).

Almost surely, 2^{141204032223041} is an apocalyptic number.

It is an amenable number.

141204032223041 is a deficient number, since it is larger than the sum of its proper divisors (22353027091).

141204032223041 is an equidigital number, since it uses as much as digits as its factorization.

141204032223041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22353027090.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 141204032223041 its reverse (140322230402141), we get a palindrome (281526262625182).

The spelling of 141204032223041 in words is "one hundred forty-one trillion, two hundred four billion, thirty-two million, two hundred twenty-three thousand, forty-one".