Base | Representation |
---|---|
bin | 11010010011010010… |
… | …01110000010110001 |
3 | 1100110002002212210102 |
4 | 31021221032002301 |
5 | 212404313202311 |
6 | 10253054042145 |
7 | 1006626536312 |
oct | 151151160261 |
9 | 40402085712 |
10 | 14120444081 |
11 | 5a966936a7 |
12 | 28a0aa9355 |
13 | 144055cc73 |
14 | 97d4aa609 |
15 | 5799c543b |
hex | 349a4e0b1 |
14120444081 has 2 divisors, whose sum is σ = 14120444082. Its totient is φ = 14120444080.
The previous prime is 14120443979. The next prime is 14120444087. The reversal of 14120444081 is 18044402141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10156608400 + 3963835681 = 100780^2 + 62959^2 .
It is an emirp because it is prime and its reverse (18044402141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14120444081 - 218 = 14120181937 is a prime.
It is a super-2 number, since 2×141204440812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14120444087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060222040 + 7060222041.
It is an arithmetic number, because the mean of its divisors is an integer number (7060222041).
Almost surely, 214120444081 is an apocalyptic number.
It is an amenable number.
14120444081 is a deficient number, since it is larger than the sum of its proper divisors (1).
14120444081 is an equidigital number, since it uses as much as digits as its factorization.
14120444081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4096, while the sum is 29.
The spelling of 14120444081 in words is "fourteen billion, one hundred twenty million, four hundred forty-four thousand, eighty-one".
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