1412124423353 has 4 divisors (see below), whose sum is σ = 1613856483840. Its totient is φ = 1210392362868.

The previous prime is 1412124423341. The next prime is 1412124423427. The reversal of 1412124423353 is 3533244212141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1412124423353 - 2⁴ = 1412124423337 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1412124423253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100866030233 + ... + 100866030246.

It is an arithmetic number, because the mean of its divisors is an integer number (403464120960).

Almost surely, 2^{1412124423353} is an apocalyptic number.

It is an amenable number.

1412124423353 is a deficient number, since it is larger than the sum of its proper divisors (201732060487).

1412124423353 is an equidigital number, since it uses as much as digits as its factorization.

1412124423353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 201732060486.

The product of its digits is 69120, while the sum is 35.

Adding to 1412124423353 its reverse (3533244212141), we get a palindrome (4945368635494).

The spelling of 1412124423353 in words is "one trillion, four hundred twelve billion, one hundred twenty-four million, four hundred twenty-three thousand, three hundred fifty-three".