14121311342002 has 4 divisors (see below), whose sum is σ = 21181967013006. Its totient is φ = 7060655671000.

The previous prime is 14121311341961. The next prime is 14121311342029. The reversal of 14121311342002 is 20024311312141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11913825592881 + 2207485749121 = 3451641^2 + 1485761^2 .

It is a super-2 number, since 2×14121311342002² (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3530327835499 + ... + 3530327835502.

Almost surely, 2^{14121311342002} is an apocalyptic number.

14121311342002 is a deficient number, since it is larger than the sum of its proper divisors (7060655671004).

14121311342002 is an equidigital number, since it uses as much as digits as its factorization.

14121311342002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7060655671003.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14121311342002 its reverse (20024311312141), we get a palindrome (34145622654143).

The spelling of 14121311342002 in words is "fourteen trillion, one hundred twenty-one billion, three hundred eleven million, three hundred forty-two thousand, two".