Base | Representation |
---|---|
bin | 10100100011001010001… |
… | …100001000110011110011 |
3 | 11222222222120021111012221 |
4 | 110203022030020303303 |
5 | 141114031202440111 |
6 | 3000421232101511 |
7 | 204011116203565 |
oct | 24431214106363 |
9 | 4888876244187 |
10 | 1412141452531 |
11 | 4a4982043287 |
12 | 1a9823394897 |
13 | a321a166c04 |
14 | 4c4c2d29335 |
15 | 26aee022371 |
hex | 148ca308cf3 |
1412141452531 has 2 divisors, whose sum is σ = 1412141452532. Its totient is φ = 1412141452530.
The previous prime is 1412141452523. The next prime is 1412141452559. The reversal of 1412141452531 is 1352541412141.
It is a weak prime.
It is an emirp because it is prime and its reverse (1352541412141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1412141452531 - 23 = 1412141452523 is a prime.
It is a super-2 number, since 2×14121414525312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1412141453531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706070726265 + 706070726266.
It is an arithmetic number, because the mean of its divisors is an integer number (706070726266).
Almost surely, 21412141452531 is an apocalyptic number.
1412141452531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412141452531 is an equidigital number, since it uses as much as digits as its factorization.
1412141452531 is an evil number, because the sum of its binary digits is even.
The product of its digits is 19200, while the sum is 34.
Adding to 1412141452531 its reverse (1352541412141), we get a palindrome (2764682864672).
The spelling of 1412141452531 in words is "one trillion, four hundred twelve billion, one hundred forty-one million, four hundred fifty-two thousand, five hundred thirty-one".
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