1412233000041 has 4 divisors (see below), whose sum is σ = 1882977333392. Its totient is φ = 941488666692.

The previous prime is 1412233000019. The next prime is 1412233000043. The reversal of 1412233000041 is 1400003322141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1412233000041 - 2¹⁵ = 1412232967273 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1412232999981 and 1412233000017.

It is not an unprimeable number, because it can be changed into a prime (1412233000043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235372166671 + ... + 235372166676.

It is an arithmetic number, because the mean of its divisors is an integer number (470744333348).

Almost surely, 2^{1412233000041} is an apocalyptic number.

It is an amenable number.

1412233000041 is a deficient number, since it is larger than the sum of its proper divisors (470744333351).

1412233000041 is an equidigital number, since it uses as much as digits as its factorization.

1412233000041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 470744333350.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1412233000041 its reverse (1400003322141), we get a palindrome (2812236322182).

The spelling of 1412233000041 in words is "one trillion, four hundred twelve billion, two hundred thirty-three million, forty-one", and thus it is an aban number.