14123231130121 has 4 divisors (see below), whose sum is σ = 14142239517312. Its totient is φ = 14104222742932.

The previous prime is 14123231130119. The next prime is 14123231130137. The reversal of 14123231130121 is 12103113232141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14123231130121 - 2¹ = 14123231130119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14123231136121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9504192481 + ... + 9504193966.

It is an arithmetic number, because the mean of its divisors is an integer number (3535559879328).

Almost surely, 2^{14123231130121} is an apocalyptic number.

It is an amenable number.

14123231130121 is a deficient number, since it is larger than the sum of its proper divisors (19008387191).

14123231130121 is an equidigital number, since it uses as much as digits as its factorization.

14123231130121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19008387190.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 14123231130121 its reverse (12103113232141), we get a palindrome (26226344362262).

The spelling of 14123231130121 in words is "fourteen trillion, one hundred twenty-three billion, two hundred thirty-one million, one hundred thirty thousand, one hundred twenty-one".