Base | Representation |
---|---|
bin | 10100100011011001100… |
… | …111100110110000010010 |
3 | 12000000122121100212201021 |
4 | 110203121213212300102 |
5 | 141120043434430224 |
6 | 3000503040230054 |
7 | 204020411363116 |
oct | 24433147466022 |
9 | 5000577325637 |
10 | 1412400311314 |
11 | 4a4aa5177763 |
12 | 1a989600b32a |
13 | a325b98b8a5 |
14 | 4c50946d746 |
15 | 26b16b061e4 |
hex | 148d99e6c12 |
1412400311314 has 4 divisors (see below), whose sum is σ = 2118600466974. Its totient is φ = 706200155656.
The previous prime is 1412400311183. The next prime is 1412400311323. The reversal of 1412400311314 is 4131130042141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1384516989025 + 27883322289 = 1176655^2 + 166983^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 353100077827 + ... + 353100077830.
Almost surely, 21412400311314 is an apocalyptic number.
1412400311314 is a deficient number, since it is larger than the sum of its proper divisors (706200155660).
1412400311314 is an equidigital number, since it uses as much as digits as its factorization.
1412400311314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 706200155659.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1412400311314 its reverse (4131130042141), we get a palindrome (5543530353455).
The spelling of 1412400311314 in words is "one trillion, four hundred twelve billion, four hundred million, three hundred eleven thousand, three hundred fourteen".
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