1412406161131 has 4 divisors (see below), whose sum is σ = 1614178469872. Its totient is φ = 1210633852392.

The previous prime is 1412406161129. The next prime is 1412406161147. The reversal of 1412406161131 is 1311616042141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1412406161131 - 2¹ = 1412406161129 is a prime.

It is a super-2 number, since 2×1412406161131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1412406161093 and 1412406161102.

It is not an unprimeable number, because it can be changed into a prime (1412406161161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100886154360 + ... + 100886154373.

It is an arithmetic number, because the mean of its divisors is an integer number (403544617468).

Almost surely, 2^{1412406161131} is an apocalyptic number.

1412406161131 is a deficient number, since it is larger than the sum of its proper divisors (201772308741).

1412406161131 is an equidigital number, since it uses as much as digits as its factorization.

1412406161131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 201772308740.

The product of its (nonzero) digits is 3456, while the sum is 31.

The spelling of 1412406161131 in words is "one trillion, four hundred twelve billion, four hundred six million, one hundred sixty-one thousand, one hundred thirty-one".