Base | Representation |
---|---|
bin | 11010010011110000… |
… | …11011111101010010 |
3 | 1100110100121112212211 |
4 | 31021320123331102 |
5 | 212411323330414 |
6 | 10253315342334 |
7 | 1010005462432 |
oct | 151170337522 |
9 | 40410545784 |
10 | 14124433234 |
11 | 5a9896881a |
12 | 28a22b19aa |
13 | 1441328902 |
14 | 97dc282c2 |
15 | 57a0123c4 |
hex | 349e1bf52 |
14124433234 has 4 divisors (see below), whose sum is σ = 21186649854. Its totient is φ = 7062216616.
The previous prime is 14124433229. The next prime is 14124433259. The reversal of 14124433234 is 43233442141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43233442141 = 43 ⋅1005428887.
It can be written as a sum of positive squares in only one way, i.e., 14124134025 + 299209 = 118845^2 + 547^2 .
It is a super-2 number, since 2×141244332342 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14124433196 and 14124433205.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3531108307 + ... + 3531108310.
Almost surely, 214124433234 is an apocalyptic number.
14124433234 is a deficient number, since it is larger than the sum of its proper divisors (7062216620).
14124433234 is an equidigital number, since it uses as much as digits as its factorization.
14124433234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7062216619.
The product of its digits is 27648, while the sum is 31.
Adding to 14124433234 its reverse (43233442141), we get a palindrome (57357875375).
The spelling of 14124433234 in words is "fourteen billion, one hundred twenty-four million, four hundred thirty-three thousand, two hundred thirty-four".
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