Base | Representation |
---|---|
bin | 1100110110001001101001… |
… | …1110101101011101101011 |
3 | 1212000021122210122212201021 |
4 | 3031202122132231131223 |
5 | 3322403330204223201 |
6 | 50012402522233311 |
7 | 2655312615605356 |
oct | 315423236553553 |
9 | 55007583585637 |
10 | 14124444211051 |
11 | 45561635962a9 |
12 | 17014b3955837 |
13 | 7b5c10ab07a5 |
14 | 36b8abb1b29d |
15 | 197621121ea1 |
hex | cd89a7ad76b |
14124444211051 has 2 divisors, whose sum is σ = 14124444211052. Its totient is φ = 14124444211050.
The previous prime is 14124444210977. The next prime is 14124444211069. The reversal of 14124444211051 is 15011244442141.
It is a strong prime.
It is an emirp because it is prime and its reverse (15011244442141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14124444211051 - 213 = 14124444202859 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14124444210998 and 14124444211016.
It is not a weakly prime, because it can be changed into another prime (14124444211151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062222105525 + 7062222105526.
It is an arithmetic number, because the mean of its divisors is an integer number (7062222105526).
Almost surely, 214124444211051 is an apocalyptic number.
14124444211051 is a deficient number, since it is larger than the sum of its proper divisors (1).
14124444211051 is an equidigital number, since it uses as much as digits as its factorization.
14124444211051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20480, while the sum is 34.
Adding to 14124444211051 its reverse (15011244442141), we get a palindrome (29135688653192).
The spelling of 14124444211051 in words is "fourteen trillion, one hundred twenty-four billion, four hundred forty-four million, two hundred eleven thousand, fifty-one".
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