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14124444211051 is a prime number
BaseRepresentation
bin1100110110001001101001…
…1110101101011101101011
31212000021122210122212201021
43031202122132231131223
53322403330204223201
650012402522233311
72655312615605356
oct315423236553553
955007583585637
1014124444211051
1145561635962a9
1217014b3955837
137b5c10ab07a5
1436b8abb1b29d
15197621121ea1
hexcd89a7ad76b

14124444211051 has 2 divisors, whose sum is σ = 14124444211052. Its totient is φ = 14124444211050.

The previous prime is 14124444210977. The next prime is 14124444211069. The reversal of 14124444211051 is 15011244442141.

It is a strong prime.

It is an emirp because it is prime and its reverse (15011244442141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14124444211051 - 213 = 14124444202859 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14124444210998 and 14124444211016.

It is not a weakly prime, because it can be changed into another prime (14124444211151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062222105525 + 7062222105526.

It is an arithmetic number, because the mean of its divisors is an integer number (7062222105526).

Almost surely, 214124444211051 is an apocalyptic number.

14124444211051 is a deficient number, since it is larger than the sum of its proper divisors (1).

14124444211051 is an equidigital number, since it uses as much as digits as its factorization.

14124444211051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20480, while the sum is 34.

Adding to 14124444211051 its reverse (15011244442141), we get a palindrome (29135688653192).

The spelling of 14124444211051 in words is "fourteen trillion, one hundred twenty-four billion, four hundred forty-four million, two hundred eleven thousand, fifty-one".