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14125103011 = 67243786509
BaseRepresentation
bin11010010011110101…
…11111011110100011
31100110101212120122101
431021322333132203
5212412011244021
610253341551231
71010014252225
oct151172773643
940411776571
1014125103011
115a99285a58
1228a2575517
131441501726
1497dd60415
1557a0e5a91
hex349ebf7a3

14125103011 has 8 divisors (see below), whose sum is σ = 14341973840. Its totient is φ = 13908410208.

The previous prime is 14125102991. The next prime is 14125103053. The reversal of 14125103011 is 11030152141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14125103011 - 215 = 14125070243 is a prime.

It is a super-2 number, since 2×141251030112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14125103011.

It is not an unprimeable number, because it can be changed into a prime (14125103711) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 120025 + ... + 206533.

It is an arithmetic number, because the mean of its divisors is an integer number (1792746730).

Almost surely, 214125103011 is an apocalyptic number.

14125103011 is a deficient number, since it is larger than the sum of its proper divisors (216870829).

14125103011 is an equidigital number, since it uses as much as digits as its factorization.

14125103011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89013.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 14125103011 its reverse (11030152141), we get a palindrome (25155255152).

The spelling of 14125103011 in words is "fourteen billion, one hundred twenty-five million, one hundred three thousand, eleven".

Divisors: 1 67 2437 86509 163279 5796103 210822433 14125103011