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141253224403 is a prime number
BaseRepresentation
bin1000001110001101011…
…0010010011111010011
3111111121011212021102211
42003203112102133103
54303241311140103
6144520230452551
713130246411524
oct2034326223723
9444534767384
10141253224403
11549a5843195
1223461504157
13104214003b5
146b9dc5484b
153a1ac7236d
hex20e35927d3

141253224403 has 2 divisors, whose sum is σ = 141253224404. Its totient is φ = 141253224402.

The previous prime is 141253224317. The next prime is 141253224407. The reversal of 141253224403 is 304422352141.

141253224403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141253224403 is a prime.

It is not a weakly prime, because it can be changed into another prime (141253224407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70626612201 + 70626612202.

It is an arithmetic number, because the mean of its divisors is an integer number (70626612202).

Almost surely, 2141253224403 is an apocalyptic number.

141253224403 is a deficient number, since it is larger than the sum of its proper divisors (1).

141253224403 is an equidigital number, since it uses as much as digits as its factorization.

141253224403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 141253224403 its reverse (304422352141), we get a palindrome (445675576544).

The spelling of 141253224403 in words is "one hundred forty-one billion, two hundred fifty-three million, two hundred twenty-four thousand, four hundred three".