Base | Representation |
---|---|
bin | 1000001110001101011… |
… | …0010010011111010011 |
3 | 111111121011212021102211 |
4 | 2003203112102133103 |
5 | 4303241311140103 |
6 | 144520230452551 |
7 | 13130246411524 |
oct | 2034326223723 |
9 | 444534767384 |
10 | 141253224403 |
11 | 549a5843195 |
12 | 23461504157 |
13 | 104214003b5 |
14 | 6b9dc5484b |
15 | 3a1ac7236d |
hex | 20e35927d3 |
141253224403 has 2 divisors, whose sum is σ = 141253224404. Its totient is φ = 141253224402.
The previous prime is 141253224317. The next prime is 141253224407. The reversal of 141253224403 is 304422352141.
141253224403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141253224403 is a prime.
It is not a weakly prime, because it can be changed into another prime (141253224407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70626612201 + 70626612202.
It is an arithmetic number, because the mean of its divisors is an integer number (70626612202).
Almost surely, 2141253224403 is an apocalyptic number.
141253224403 is a deficient number, since it is larger than the sum of its proper divisors (1).
141253224403 is an equidigital number, since it uses as much as digits as its factorization.
141253224403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 141253224403 its reverse (304422352141), we get a palindrome (445675576544).
The spelling of 141253224403 in words is "one hundred forty-one billion, two hundred fifty-three million, two hundred twenty-four thousand, four hundred three".
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