Base | Representation |
---|---|
bin | 11010010011111010… |
… | …00010111010111011 |
3 | 1100110102212221011211 |
4 | 31021331002322323 |
5 | 212412131011103 |
6 | 10253401303551 |
7 | 1010021653666 |
oct | 151175027273 |
9 | 40412787154 |
10 | 14125641403 |
11 | 5a99613505 |
12 | 28a2794bb7 |
13 | 144165c7c3 |
14 | 9800606dd |
15 | 57a1a036d |
hex | 349f42ebb |
14125641403 has 2 divisors, whose sum is σ = 14125641404. Its totient is φ = 14125641402.
The previous prime is 14125641391. The next prime is 14125641419. The reversal of 14125641403 is 30414652141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14125641403 - 213 = 14125633211 is a prime.
It is a super-2 number, since 2×141256414032 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14125641703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062820701 + 7062820702.
It is an arithmetic number, because the mean of its divisors is an integer number (7062820702).
Almost surely, 214125641403 is an apocalyptic number.
14125641403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14125641403 is an equidigital number, since it uses as much as digits as its factorization.
14125641403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
The spelling of 14125641403 in words is "fourteen billion, one hundred twenty-five million, six hundred forty-one thousand, four hundred three".
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