Base | Representation |
---|---|
bin | 1100110110011110010111… |
… | …1000011000111101111101 |
3 | 1212000211000021202122112120 |
4 | 3031213211320120331331 |
5 | 3323001222033420331 |
6 | 50015122340153153 |
7 | 2655600451003530 |
oct | 315474570307575 |
9 | 55024007678476 |
10 | 14130004201341 |
11 | 45585570042a6 |
12 | 17025a59987b9 |
13 | 7b65b8969b82 |
14 | 36bc7830ca17 |
15 | 1978492e1796 |
hex | cd9e5e18f7d |
14130004201341 has 16 divisors (see below), whose sum is σ = 21533657539200. Its totient is φ = 8073454652928.
The previous prime is 14130004201337. The next prime is 14130004201363. The reversal of 14130004201341 is 14310240003141.
It is not a de Polignac number, because 14130004201341 - 22 = 14130004201337 is a prime.
It is a super-2 number, since 2×141300042013412 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14130004201301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34519276 + ... + 34926213.
It is an arithmetic number, because the mean of its divisors is an integer number (1345853596200).
Almost surely, 214130004201341 is an apocalyptic number.
It is an amenable number.
14130004201341 is a deficient number, since it is larger than the sum of its proper divisors (7403653337859).
14130004201341 is an equidigital number, since it uses as much as digits as its factorization.
14130004201341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69455188.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 14130004201341 its reverse (14310240003141), we get a palindrome (28440244204482).
The spelling of 14130004201341 in words is "fourteen trillion, one hundred thirty billion, four million, two hundred one thousand, three hundred forty-one".
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