Base | Representation |
---|---|
bin | 100000001000001100101010… |
… | …011000001011110100011011 |
3 | 200112022020011111022011100001 |
4 | 200020030222120023310123 |
5 | 122010033110023212133 |
6 | 1220304413151553431 |
7 | 41522435353225555 |
oct | 4010145230136433 |
9 | 615266144264301 |
10 | 141300840054043 |
11 | 4102839356147a |
12 | 13a2107152b877 |
13 | 60ac7c5873027 |
14 | 26c6dd626a4d5 |
15 | 115085c04b87d |
hex | 80832a60bd1b |
141300840054043 has 2 divisors, whose sum is σ = 141300840054044. Its totient is φ = 141300840054042.
The previous prime is 141300840053993. The next prime is 141300840054089. The reversal of 141300840054043 is 340450048003141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141300840054043 - 217 = 141300839922971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 141300840053993 and 141300840054011.
It is not a weakly prime, because it can be changed into another prime (141300840055043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70650420027021 + 70650420027022.
It is an arithmetic number, because the mean of its divisors is an integer number (70650420027022).
Almost surely, 2141300840054043 is an apocalyptic number.
141300840054043 is a deficient number, since it is larger than the sum of its proper divisors (1).
141300840054043 is an equidigital number, since it uses as much as digits as its factorization.
141300840054043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 92160, while the sum is 37.
Adding to 141300840054043 its reverse (340450048003141), we get a palindrome (481750888057184).
The spelling of 141300840054043 in words is "one hundred forty-one trillion, three hundred billion, eight hundred forty million, fifty-four thousand, forty-three".
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