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1413023311131 = 3471007770377
BaseRepresentation
bin10100100011111110110…
…000001010010100011011
312000002021000122112210120
4110203332300022110123
5141122332431424011
63001044533244323
7204042014654115
oct24437660122433
95002230575716
101413023311131
114a5294904743
121a9a2a7936a3
13a332aa7b133
144c5680c23b5
1526b51668a06
hex148fec0a51b

1413023311131 has 4 divisors (see below), whose sum is σ = 1884031081512. Its totient is φ = 942015540752.

The previous prime is 1413023311129. The next prime is 1413023311199. The reversal of 1413023311131 is 1311133203141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1413023311131 - 21 = 1413023311129 is a prime.

It is a super-2 number, since 2×14130233111312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1413023312131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235503885186 + ... + 235503885191.

It is an arithmetic number, because the mean of its divisors is an integer number (471007770378).

Almost surely, 21413023311131 is an apocalyptic number.

1413023311131 is a deficient number, since it is larger than the sum of its proper divisors (471007770381).

1413023311131 is an equidigital number, since it uses as much as digits as its factorization.

1413023311131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 471007770380.

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 1413023311131 its reverse (1311133203141), we get a palindrome (2724156514272).

The spelling of 1413023311131 in words is "one trillion, four hundred thirteen billion, twenty-three million, three hundred eleven thousand, one hundred thirty-one".

Divisors: 1 3 471007770377 1413023311131