Base | Representation |
---|---|
bin | 10100100011111110110… |
… | …000001010010100011011 |
3 | 12000002021000122112210120 |
4 | 110203332300022110123 |
5 | 141122332431424011 |
6 | 3001044533244323 |
7 | 204042014654115 |
oct | 24437660122433 |
9 | 5002230575716 |
10 | 1413023311131 |
11 | 4a5294904743 |
12 | 1a9a2a7936a3 |
13 | a332aa7b133 |
14 | 4c5680c23b5 |
15 | 26b51668a06 |
hex | 148fec0a51b |
1413023311131 has 4 divisors (see below), whose sum is σ = 1884031081512. Its totient is φ = 942015540752.
The previous prime is 1413023311129. The next prime is 1413023311199. The reversal of 1413023311131 is 1311133203141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1413023311131 - 21 = 1413023311129 is a prime.
It is a super-2 number, since 2×14130233111312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1413023312131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235503885186 + ... + 235503885191.
It is an arithmetic number, because the mean of its divisors is an integer number (471007770378).
Almost surely, 21413023311131 is an apocalyptic number.
1413023311131 is a deficient number, since it is larger than the sum of its proper divisors (471007770381).
1413023311131 is an equidigital number, since it uses as much as digits as its factorization.
1413023311131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 471007770380.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 1413023311131 its reverse (1311133203141), we get a palindrome (2724156514272).
The spelling of 1413023311131 in words is "one trillion, four hundred thirteen billion, twenty-three million, three hundred eleven thousand, one hundred thirty-one".
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