1413044242433 has 4 divisors (see below), whose sum is σ = 1413055770048. Its totient is φ = 1413032714820.

The previous prime is 1413044242417. The next prime is 1413044242453. The reversal of 1413044242433 is 3342424403141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1413044242433 - 2⁴ = 1413044242417 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1413044242393 and 1413044242402.

It is not an unprimeable number, because it can be changed into a prime (1413044242403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5577941 + ... + 5825762.

It is an arithmetic number, because the mean of its divisors is an integer number (353263942512).

Almost surely, 2^{1413044242433} is an apocalyptic number.

It is an amenable number.

1413044242433 is a deficient number, since it is larger than the sum of its proper divisors (11527615).

1413044242433 is a wasteful number, since it uses less digits than its factorization.

1413044242433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11527614.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 1413044242433 its reverse (3342424403141), we get a palindrome (4755468645574).

The spelling of 1413044242433 in words is "one trillion, four hundred thirteen billion, forty-four million, two hundred forty-two thousand, four hundred thirty-three".