Base | Representation |
---|---|
bin | 100000001000010110001111… |
… | …001000100110111010000011 |
3 | 200112100012200221121001102211 |
4 | 200020112033020212322003 |
5 | 122010220133310412344 |
6 | 1220313233231322551 |
7 | 41523251203606612 |
oct | 4010261710467203 |
9 | 615305627531384 |
10 | 141311120404099 |
11 | 41031789549648 |
12 | 13a23060380457 |
13 | 60b077366b2b9 |
14 | 26c76cd729879 |
15 | 1150c5e836334 |
hex | 80858f226e83 |
141311120404099 has 2 divisors, whose sum is σ = 141311120404100. Its totient is φ = 141311120404098.
The previous prime is 141311120404063. The next prime is 141311120404163. The reversal of 141311120404099 is 990404021113141.
It is a weak prime.
It is an emirp because it is prime and its reverse (990404021113141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 141311120404099 - 29 = 141311120403587 is a prime.
It is not a weakly prime, because it can be changed into another prime (141311120408099) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70655560202049 + 70655560202050.
It is an arithmetic number, because the mean of its divisors is an integer number (70655560202050).
Almost surely, 2141311120404099 is an apocalyptic number.
141311120404099 is a deficient number, since it is larger than the sum of its proper divisors (1).
141311120404099 is an equidigital number, since it uses as much as digits as its factorization.
141311120404099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 40.
The spelling of 141311120404099 in words is "one hundred forty-one trillion, three hundred eleven billion, one hundred twenty million, four hundred four thousand, ninety-nine".
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