Base | Representation |
---|---|
bin | 1100110110100010011111… |
… | …1111110001110101000001 |
3 | 1212000220212120222112021200 |
4 | 3031220213333301311001 |
5 | 3323011010014400213 |
6 | 50015424403011413 |
7 | 2655640110223332 |
oct | 315504777616501 |
9 | 55026776875250 |
10 | 14131113434433 |
11 | 4558a76155566 |
12 | 1702855369b69 |
13 | 7b6734701308 |
14 | 36bd41772289 |
15 | 1978b189d273 |
hex | cda27ff1d41 |
14131113434433 has 24 divisors (see below), whose sum is σ = 20439489907200. Its totient is φ = 9407877767424.
The previous prime is 14131113434419. The next prime is 14131113434467. The reversal of 14131113434433 is 33443431113141.
14131113434433 is a `hidden beast` number, since 1 + 41 + 31 + 113 + 43 + 4 + 433 = 666.
It is not a de Polignac number, because 14131113434433 - 26 = 14131113434369 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14131113434533) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 44066448 + ... + 44385966.
It is an arithmetic number, because the mean of its divisors is an integer number (851645412800).
Almost surely, 214131113434433 is an apocalyptic number.
It is an amenable number.
14131113434433 is a deficient number, since it is larger than the sum of its proper divisors (6308376472767).
14131113434433 is a wasteful number, since it uses less digits than its factorization.
14131113434433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 326221 (or 326218 counting only the distinct ones).
The product of its digits is 62208, while the sum is 36.
Adding to 14131113434433 its reverse (33443431113141), we get a palindrome (47574544547574).
The spelling of 14131113434433 in words is "fourteen trillion, one hundred thirty-one billion, one hundred thirteen million, four hundred thirty-four thousand, four hundred thirty-three".
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