Search a number
-
+
1413111400411 = 5197271909063
BaseRepresentation
bin10100100100000100000…
…000001100011111011011
312000002111011101221120111
4110210010000030133123
5141123023004303121
63001101401305151
7204044134501144
oct24440400143733
95002434357514
101413111400411
114a532a6004a7
121a9a541951b7
13a33430b1479
144c575a92acb
1526b592692e1
hex1490400c7db

1413111400411 has 4 divisors (see below), whose sum is σ = 1413383314672. Its totient is φ = 1412839486152.

The previous prime is 1413111400339. The next prime is 1413111400447. The reversal of 1413111400411 is 1140041113141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1413111400411 - 215 = 1413111367643 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1413111400451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135949335 + ... + 135959728.

It is an arithmetic number, because the mean of its divisors is an integer number (353345828668).

Almost surely, 21413111400411 is an apocalyptic number.

1413111400411 is a deficient number, since it is larger than the sum of its proper divisors (271914261).

1413111400411 is an equidigital number, since it uses as much as digits as its factorization.

1413111400411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 271914260.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 1413111400411 its reverse (1140041113141), we get a palindrome (2553152513552).

The spelling of 1413111400411 in words is "one trillion, four hundred thirteen billion, one hundred eleven million, four hundred thousand, four hundred eleven".

Divisors: 1 5197 271909063 1413111400411