Base | Representation |
---|---|
bin | 1100110110100010100000… |
… | …0111010111110110111011 |
3 | 1212000220212201201200010012 |
4 | 3031220220013113312323 |
5 | 3323011011022101321 |
6 | 50015424513412135 |
7 | 2655640133154341 |
oct | 315505007276673 |
9 | 55026781650105 |
10 | 14131115425211 |
11 | 4558a77295234 |
12 | 1702855b6a04b |
13 | 7b6734c4a4a5 |
14 | 36bd41b2d991 |
15 | 1978b1b4305b |
hex | cda281d7dbb |
14131115425211 has 4 divisors (see below), whose sum is σ = 14186100310392. Its totient is φ = 14076130540032.
The previous prime is 14131115425199. The next prime is 14131115425381. The reversal of 14131115425211 is 11252451113141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14131115425211 is a prime.
It is a super-2 number, since 2×141311154252112 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14131115485211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27492442205 + ... + 27492442718.
It is an arithmetic number, because the mean of its divisors is an integer number (3546525077598).
Almost surely, 214131115425211 is an apocalyptic number.
14131115425211 is a deficient number, since it is larger than the sum of its proper divisors (54984885181).
14131115425211 is an equidigital number, since it uses as much as digits as its factorization.
14131115425211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54984885180.
The product of its digits is 4800, while the sum is 32.
Adding to 14131115425211 its reverse (11252451113141), we get a palindrome (25383566538352).
The spelling of 14131115425211 in words is "fourteen trillion, one hundred thirty-one billion, one hundred fifteen million, four hundred twenty-five thousand, two hundred eleven".
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