Base | Representation |
---|---|
bin | 10100100100000100000… |
… | …001011000010111101011 |
3 | 12000002111011222201220121 |
4 | 110210010001120113223 |
5 | 141123023044224321 |
6 | 3001101412104111 |
7 | 204044140234234 |
oct | 24440401302753 |
9 | 5002434881817 |
10 | 1413111711211 |
11 | 4a532a7a2a62 |
12 | 1a9a54305037 |
13 | a334318ca85 |
14 | 4c575b3408b |
15 | 26b592cb441 |
hex | 149040585eb |
1413111711211 has 4 divisors (see below), whose sum is σ = 1413158389632. Its totient is φ = 1413065032792.
The previous prime is 1413111711199. The next prime is 1413111711217. The reversal of 1413111711211 is 1121171113141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1413111711211 - 213 = 1413111703019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1413111711217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23293771 + ... + 23354356.
It is an arithmetic number, because the mean of its divisors is an integer number (353289597408).
Almost surely, 21413111711211 is an apocalyptic number.
1413111711211 is a deficient number, since it is larger than the sum of its proper divisors (46678421).
1413111711211 is an equidigital number, since it uses as much as digits as its factorization.
1413111711211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46678420.
The product of its digits is 168, while the sum is 25.
Adding to 1413111711211 its reverse (1121171113141), we get a palindrome (2534282824352).
The spelling of 1413111711211 in words is "one trillion, four hundred thirteen billion, one hundred eleven million, seven hundred eleven thousand, two hundred eleven".
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