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1413113346713 is a prime number
BaseRepresentation
bin10100100100000100000…
…111100111101010011001
312000002111022001211101202
4110210010013213222121
5141123024004043323
63001101511123545
7204044160155405
oct24440407475231
95002438054352
101413113346713
114a533070a812
121a9a549735b5
13a3343613323
144c57603c105
1526b59500d28
hex149041e7a99

1413113346713 has 2 divisors, whose sum is σ = 1413113346714. Its totient is φ = 1413113346712.

The previous prime is 1413113346703. The next prime is 1413113346719. The reversal of 1413113346713 is 3176433113141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1347345205504 + 65768141209 = 1160752^2 + 256453^2 .

It is an emirp because it is prime and its reverse (3176433113141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1413113346713 - 212 = 1413113342617 is a prime.

It is not a weakly prime, because it can be changed into another prime (1413113346719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706556673356 + 706556673357.

It is an arithmetic number, because the mean of its divisors is an integer number (706556673357).

Almost surely, 21413113346713 is an apocalyptic number.

It is an amenable number.

1413113346713 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413113346713 is an equidigital number, since it uses as much as digits as its factorization.

1413113346713 is an evil number, because the sum of its binary digits is even.

The product of its digits is 54432, while the sum is 38.

Adding to 1413113346713 its reverse (3176433113141), we get a palindrome (4589546459854).

The spelling of 1413113346713 in words is "one trillion, four hundred thirteen billion, one hundred thirteen million, three hundred forty-six thousand, seven hundred thirteen".