Base | Representation |
---|---|
bin | 100000001000010110100001… |
… | …101010100111111101111011 |
3 | 200112100020111121121202211122 |
4 | 200020112201222213331323 |
5 | 122010221302403424402 |
6 | 1220313324135215455 |
7 | 41523262000354442 |
oct | 4010264152477573 |
9 | 615306447552748 |
10 | 141311431311227 |
11 | 41031928aa2791 |
12 | 13a2312851758b |
13 | 60b07c2bb7808 |
14 | 26c771cb3bd59 |
15 | 1150c7bc9bca2 |
hex | 8085a1aa7f7b |
141311431311227 has 2 divisors, whose sum is σ = 141311431311228. Its totient is φ = 141311431311226.
The previous prime is 141311431311191. The next prime is 141311431311233. The reversal of 141311431311227 is 722113134113141.
141311431311227 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141311431311227 - 232 = 141307136343931 is a prime.
It is not a weakly prime, because it can be changed into another prime (141311431311257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70655715655613 + 70655715655614.
It is an arithmetic number, because the mean of its divisors is an integer number (70655715655614).
Almost surely, 2141311431311227 is an apocalyptic number.
141311431311227 is a deficient number, since it is larger than the sum of its proper divisors (1).
141311431311227 is an equidigital number, since it uses as much as digits as its factorization.
141311431311227 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12096, while the sum is 35.
Adding to 141311431311227 its reverse (722113134113141), we get a palindrome (863424565424368).
The spelling of 141311431311227 in words is "one hundred forty-one trillion, three hundred eleven billion, four hundred thirty-one million, three hundred eleven thousand, two hundred twenty-seven".
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