Base | Representation |
---|---|
bin | 1100110110100101111011… |
… | …1000010101011011110011 |
3 | 1212001000020202121210100022 |
4 | 3031221132320111123303 |
5 | 3323014401230330003 |
6 | 50020100014514055 |
7 | 2656001660653454 |
oct | 315513670253363 |
9 | 55030222553308 |
10 | 14132034230003 |
11 | 45593a89a0938 |
12 | 1702a7180592b |
13 | 7b68503c9271 |
14 | 36bdcbb8312b |
15 | 197917636738 |
hex | cda5ee156f3 |
14132034230003 has 4 divisors (see below), whose sum is σ = 14222047187040. Its totient is φ = 14042021272968.
The previous prime is 14132034229933. The next prime is 14132034230051. The reversal of 14132034230003 is 30003243023141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14132034230003 - 218 = 14132033967859 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14132034230203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45006478283 + ... + 45006478596.
It is an arithmetic number, because the mean of its divisors is an integer number (3555511796760).
Almost surely, 214132034230003 is an apocalyptic number.
14132034230003 is a deficient number, since it is larger than the sum of its proper divisors (90012957037).
14132034230003 is an equidigital number, since it uses as much as digits as its factorization.
14132034230003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 90012957036.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 14132034230003 its reverse (30003243023141), we get a palindrome (44135277253144).
The spelling of 14132034230003 in words is "fourteen trillion, one hundred thirty-two billion, thirty-four million, two hundred thirty thousand, three".
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