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141322433221481 is a prime number
BaseRepresentation
bin100000001000100000110001…
…011011100101001101101001
3200112101021220100122201110012
4200020200301123211031221
5122010411320401041411
61220322343552301305
741524131432144521
oct4010406133451551
9615337810581405
10141322433221481
11410365643157a6
1213a25298b41835
1360b1857330795
1426c8083d88681
1511511c2ab718b
hex8088316e5369

141322433221481 has 2 divisors, whose sum is σ = 141322433221482. Its totient is φ = 141322433221480.

The previous prime is 141322433221339. The next prime is 141322433221573. The reversal of 141322433221481 is 184122334223141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141314558256400 + 7874965081 = 11887580^2 + 88741^2 .

It is a cyclic number.

It is not a de Polignac number, because 141322433221481 - 246 = 70953689043817 is a prime.

It is a super-2 number, since 2×1413224332214812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (141322433121481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70661216610740 + 70661216610741.

It is an arithmetic number, because the mean of its divisors is an integer number (70661216610741).

Almost surely, 2141322433221481 is an apocalyptic number.

It is an amenable number.

141322433221481 is a deficient number, since it is larger than the sum of its proper divisors (1).

141322433221481 is an equidigital number, since it uses as much as digits as its factorization.

141322433221481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 221184, while the sum is 41.

The spelling of 141322433221481 in words is "one hundred forty-one trillion, three hundred twenty-two billion, four hundred thirty-three million, two hundred twenty-one thousand, four hundred eighty-one".